Tuesday, 17 March 2009

IITJEE Solved problem

IITJEE solved problems are two among those problems send to us by visitors of our blog as their querries. You can also send us your querries to us to get them solved.

Problem 1. Two masses m1 and m2 are connected by a spring of spring constant k and are placed on a frictionless horizontal surface. Initially the spring is stretched through a distance x0 when the system is released from rest. Find the distance moved by the messes before they again come to rest.

Solution.

Consider blocks plus spring a system and if no external forces acts on the sysyem then centre of mass of system will remain at rest. Mean position of two SHM's would be the unstretched position.If m1 moves towards right through a distance x1 and m2 moves towards left through a distance x2before spring acquires natural length then
x1+ x2= x0 .....................(1)
where x1 and x2 would be the amplitudes of blocks m1 and m2 resp. Since centre of mass of system will remain same so,
m1x1=m2x2
thus from 1
x1=m2x0/(m1 + m2)
x2=m1x0/(m1 + m2)
to get back to rest position masses m1 and m2 would have to travel distances x1 and x2 resp. , so total distance travelled by m1 before comming to rest is
2m2x0/(m1 + m2)
and total distance travelled by m2 before comming to rest is,
2m1x0/(m1 + m2)

Problem 2. Suppose the surface charge density over a sphere of radius R depends on a polar angle θ as σ=σ0cosθ, where σ0 is a positive constant. Find the electric field strength vector inside the given sphere.
Solution.
You can visualize such a charge distribution as a result of a small relative shift of two uniformly charged balls of radius R, whose charges are equal in magnitude but opposite in sign. In such a representation inner charges cancel out each other and only charges on the surface survives having charge density σ=σ0cosθ. Charge density is maximum along +Z and -Z where the distance between the surfaces is maximum.


Electric field due to positively charged sphere E+r+/3ε0
Electric field due to positively charged sphere E-=-ρr-/3ε0
Electric field at P
E = E++E- =ρ(r+-r-)/3ε0
or,
Ea/3ε0=ρakˆ/3ε0
now,
ρa = charge per unit area =σ0
hence,
E0kˆ/3ε0

Saturday, 7 March 2009

Free Physics Ebooks

Dear Students

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We have added one more Ebook.
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Physics Expert

Friday, 6 February 2009

IITJEE Problems: Modern Physics

Q 1. What is the Kinetic energy of the photoelectrons ejected from a tungsten surface by UV light of wavelength 1940Å ? Express the result in eV. The photoelectric threshold of tungsten is 2300Å .
Ans. K=1 eV
Q 2. The work function of sodium is 2 eV.
(a) Find the maximum energy of the photoelectrons ejected when a sodium surface is illuminated with light of 3105Å.
(b) Calculate the maximum wavelength of the light that would produce photoelectric effect.
Ans. 2 eV , 6210Å
Q 3. A small plate of metal (work function 1.17 eV) is placed at a distance 2 m from monochromatic light source of wavelength 4.8x10-7and power 1.0 watt. The light falls normally on plate. Find the number of photons striking the metal plate per square meter per second. If a constant uniform magnetic field of strength 10-4 tesla is applied parallel to the metal surface , find the radius of the largest circular path followed by the emitted photoelectrons.
Ans. 4.82 x1016 , 4.0 cm
Q 4. Calculate the wavelength of the wave associated with :
(a) 1 MeV photon
(b) 1 MeV proton
Ans. 1.242x10-10 cm, 2.84x10-12 cm
Q 5. The molecules of a certain gas at 320 K have a rms speed of .499 Km/sec. Calculate the De Brogli wavelength of these molecules. What is the gas?
Ans. 0.25Å , O16

Friday, 9 January 2009

IITJEE Problems : Optics

Q 1. A concave mirror of radius of curvature 1m is placed at bottom of a tank of water. The mirror forms an image of the sun , when it is directly overhead. Calculate the distance of the images from the mirror for different depths, 80 cm and 40 cm of the water in the tank. (ans=50 cm , 47.5 cm)
Q 2. A pin is placed 10 cm in front of convex lens of focal length 20 cm made of material of refrective index 1.5. The surface of lens farther away from the pin is silvered and has a radius of curvature 22 cm. Determine the position of the final image. Is the image real or virtual.(Ans -11 cm)
Q 3. An object is placed 50 cm from the surface of a glass sphere of radius 12 cm along the diameter . Where will the final image be formed by reflection on both the surfaces? Refractive index of glass is 1.60 (Ans +9.5 cm)
Q 4. A bi-convex lens of radii of curvature 30.0 cm each is placed on the surface of water so that the lower surface is only immersed . An illuminated object 40 cm deep is observed vertically through the lens and water. Find the position of the image. Refractive index of air-glass=3/2 and of glass-air=4/3 . (ans -90 cm)
Q 5. Interference pattern is obtained with two coherent light sources of intensity ratio n. Show that in the interference pattern
(Imax-Imin)/(Imax+Imin)=2√n/(n+1)

Friday, 2 January 2009

IITJEE/AIEEE 2009 Information

IITJEE 2009 Information

1.The IIT JEE for 2009 would be held for 12th April 2009

2. The JEE examination would be objective type and would contain 2 papers of 3 hours each Paper-1 would be held from 9 AM to 12 noon and the Paper-2 would be held from 2 PM to 5 PM.Each paper would have separate sections for Physics,Chemistry and Mathematics and would be designed to test comprehension,reasoning and analytical ability of the candidates.

3.This year the examination would be held for 12 IIT’s,IT-BHU Varanasi and ISMU Dhandbad.


AIIEE 2009 information

1. The eighth all India Engineering Entrance Examination will be held on 26th April,2009 all over India and abroad.

2 This is for admissions in B.E/B.Tech and B.Arch/B. Planning in various national level institutes like NIT’s,IIIT’s,Deemed Universities and government funded institutions and States like Haryana and Uttaranchal

3. This examination will be held in two parts viz B.E./B.Tech from 9:30 a.m. to 12:30 p.m. and for B.Arch./B. Planning from 1400 hrs to 1700 hrs.

4. Materials to be brought on the day of examination Admit Card and Ball Point Pen of good quality. For Aptitude Test in Architecture, the candidates are advised to bring their own Card Board, geometry box set, pencils,erasers and color pencils or crayons.
5. Rough work All rough work is to be done in the Test Booklet only. The candidate should NOT do any rough work or put stray mark on the Answer Sheet.

IITJEE PHYSICS: PHYSICSCATALYST

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Site Name
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We have put lot of effort to build the site.I hope students will find it very useful in there studies for competetion,board,physics homework.
Thanks
Physics Expert

Sunday, 21 December 2008

IITJEE Study Material:Elasticity

-Elasticity is the property of material body to regain its original condition on removal of deforming forces.
-Bodies which can recover their original condition on removal of deforming forces are perfectly elastic bodies .
-Bodies which does not have tendency to recover their original condition on removal of deforming forces are called plastic bodies.
-There are no perfectly elastic or plastic bodies and actual bodies lie between two extremes.
(1) STRESS
-Stress is the restoring force per unit area set up inside the body and is measured by the magnitude of deforming force acting on unit area of the body within the elastic limits of the body.
Magnitude of stress=F/A where, Fis the force applied and A is the area of crosssection of the body.
-S.I. unit of sterss is N/m2.-Dimensional formula of stress is[ML1T-2].
(A) Normal Stress:- If elastic forces developed are perpandicular to the area of cross-section of the body then the stress developed is known as normal stress.
(B) Tangential Stress:- Tangential or shearing stress developes in a body when elastic restoring forces are parallel to the cross-sectional area of the body and the body gets sheared through a certain angle.
(2) STRAIN
-When a body is under a system of forces or couples in equilibrium then a change is produced in dimensions of the body and this fractional change produced in the body is called Strain.
(A) longitudinal strain=Δl/l, where l is the original length and Δl is the change in length.
(B) volume strain=ΔV/V, where V is the original volume and ΔV is the change in volume.
(C) if the deforming forces produces change in shape of the body then the strain is called shearing strain.
-Strain is an dimensionless quantity.
(3)HOOK'S LAW
-Hook's law states that 'For small deformations, within elastic limits, stress is directly proportional to strain'.
Thus, stress ∝ strain
or, stress/strain=constant-This constant is known as modulus of elasticity of given material.
(4)MODULUS OF ELASTICITY
(A) Young's modulus of elasticity:-
-Young's modulus of elasticity is given by
Y=longitudinal Stress/longitudinal Stress
= (F/A)/(Δl/l)
=Fl/AΔl
-It has dimensions of pressure.
(B) Bulk modulus of elasticity:-
-Bulk modulus of elasticity is the ratio of normal stress to volume strain within elastic limits.
-It is denoted by k and
K=FV/AΔV
(C) Modulus of rigidity:-
-When a body is sheared , the ratio of tangential stress to the shearing strain within elastic limits is called modulus of rigidity.